Finish the steps below to write a quadratic function for the parabola shown. use the vertex form, f(x) = a(x – h)2 + k, and substitute in the values for h and k. f(x) = a(x – 5)2 + 3 use another point and substitute in values for x and f(x). solve for a. 5 = a(6 – 5)2 + 3 write the function, using the values for h, k, and a.

The quadratic function is f(x) = 2( x - 5 )² + 3

Discriminant of quadratic equation ( ax² + bx + c = 0 ) could be calculated by using :

From the value of Discriminant , we know how many solutions the equation has by condition :

D < 0 → No Real Roots

D = 0 → One Real Root

D > 0 → Two Real Roots

An axis of symmetry of quadratic equation y = ax² + bx + c is :

Let us now tackle the problem!

Given:

The stationary point (h , k) = (5 , 3)

The point ( 6 , 5 ) passes through graph , then:

The quadratic function will be :

Grade: High School

Subject: Mathematics

Chapter: Quadratic Equations

Keywords: Quadratic , Equation , Discriminant , Real , Number

i'm sure goog can you get that answer

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18