Use the student's t distribution to find tc for a 0.99 confidence level when the sample is 13. (round your answer to three decimal places.)

We need to find the critical t-value at confidence level of 0.99 for the given sample size. Since the sample size is 13, the degree of freedom(df) will be 12, as:

df = Sample Size - 1

So, we need to check the critical value column under confidence level 0.99 and across the row showing df = 12. From the t-table this value comes out to be 3.055. 

A picture of the t-table showing the result is attached with. Highlighted cell show the result of this question.

Google it that might work