Don’t say a or just me plz and thx

A)P = 2l+2w
P =2l+2w≥40 should be
 2*6+2w≥40
12+2w≥40
2w≥40-12, 2w≥28
b) 2w≥28
w≥14
so smallest is 14

Information Given

Perimeter of a Parallelogram = 2l + 2w
Given that length = 6 feet and  Perimeter is no less that 40 feet


Construct the inequality

2(6) + 2w ≥ 40

12 + 2w ≥ 40


Take away 12 from both sides

2w ≥ 40 - 12

2w ≥ 28


Divide by 2 on both sides

w ≥ 14

The smallest possible value of the width is 14 feet


Answer (a) inequality: 12 + 2w ≥ 40 (b) Smallest value of w = 14.

It will b. 975 because i’m guessin

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

0 = ( 2 - 4 ) ( p + q )0 = ( 2 - 4 ) ( 2 + 5 i ),   by multiplying these0 = ( 4 + 10 i - 8 - 20 i )0 = 4 - 8 + 10 i - 20 i0 = - 4 -10 i   0 = 2 ( - 2 - 5 i )0 / 2 = - 2 - 5 i- 2 - 5 i = 0- 5 i = 2i = 2 / - 5