In △jkl, solve for x. triangle jkl where angle k is a right angle. kl measures 34. jl measures x. angle j measures 27 degrees. 66.73 74.89 15.44 38.16

For this case, the first thing we should do is use the following trigonometric relationship:
 sine (x) = (C.O) / (h)
 Where,
 x: angle
 C.O: opposite leg.
 h: hypotenuse
 Substituting values:
 sine (27) = (34) / (x)
 Clearing x:
 x = (34) / (sine (27))
 x = 74.89
 
 x = 74.89