One root of the equation x2+6x+q=0 is twice the other root. find q and the roots.

q = 18 , roots = -3&-6

Step-by-step explanation:

Let :-

First root = xSecond root = 2x

We know ,

Sum of roots = -b/ax + 2x = -6/1 3x = -6 x = -3

And ,

Product of roots = c/ax * 2x = q 2x²= q q = 2* -3² q = 2* 9 q = 18

Roots :-

x = -32x = -6

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