2v squared +4v-2 solved by completing the square

-2v² + 4v - 2

you would first divide the whole polynomial by -2 because -2 is the common factor of all the terms.

-2(v² - 2v + 1)

now factor the polynomial inside the parenthesis.

-2 ( v - 1)( v - 1)

so the final answer is

-2( v - 1)²