Find three consecutive odd integers such that 5 times the third is 94 than the second

Define the numbers

First the first odd integer be x.
1st odd = x
2nd odd = x + 2
3rd odd = x + 4


Form the equation and solve for x

5(x + 4) - 94 = x + 2
5x + 20 - 94 = x + 2
5x - 74 = x + 2
5x - x = 2 + 74
4x = 76
x = 19


Find the 3 consecutive integers

1st = x = 19
2nd = x + 2 = 19 + 2 = 21
3rd = x + 4 = 19 + 4 = 23


The 3 consecutive odd numbers are 19, 21 and 23

4+2=-2. 1+2=3. y=-2/3x+b. 2=4/3+b. 2/3=b. the answer is y= -2/3x+2/3