Im really stuck on this the two dot plots below show the heights of some sixth graders and some seventh graders: two dot plots are shown one below the other. the title for the top dot plot is sixth graders and the title for the bottom plot is seventh graders. below the line for each dot plot is written height followed by inches in parentheses. there are markings from 52 to 57 on the top line and the bottom line at intervals of one. for the top line there are 2 dots above the first mark, 1 dot above the second mark, 1 dot above the third mark and 2 dots above the fourth mark. for the bottom line, there are 2 dots for the fifth mark, there are 4 dots above the sixth mark. the mean absolute deviation (mad) for the first set of data is 1.2 and the mad for the second set of data is 0.4. approximately how many times the variability in the heights of the seventh graders is the variability in the heights of the sixth graders? (round all values to the tenths place.) 3.2 3.0 1.5 0.8

The number of times the  variability in the heights of the seventh graders is the variability in the heights of the sixth graders is:

                          3.0

Step-by-step explanation:

In order to find the variability between the two sets we divide the mean absolute deviation of the first set of data by the mean absolute deviation of the second set of the data.

The MAD of first set of data is: 1.2

and MAD of second set of data is: 0.4

Hence, let n be the number of times the variability in the heights of the seventh graders is the variability in the heights of the sixth graders.

i.e.

Hence, the answer is:

3.0

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

answer: 298143

step-by-step explanation: