Aprojectile is shot into the air following the path, h(x) = 3x 2 - 12x + 5. at what time, value of x, will it reach a maximum height? a.) x = 1 b.) x = 2 c.) x = 4 d.) x = 5

Option B. x = 2

Step-by-step explanation:

A projectile is shot into the air following the path as h(x) = 3x² - 12x + 5

We have to find the value of x for which the height of the projectile is maximum.

Since projectile follows the path h(x) = 3x² - 12x + 5, a quadratic equation which means the path is in the form of a parabola.

Maximum height means vertex, which will be at the maximum height of the parabolic path.

Since x-coordinate of vertex of a parabola is represented by h =

From the given quadratic equation which is in the form of h(x) = ax² + bx + c

a = 3

b = -12

c = 5

Therefore, maximum height will be at x =

x = 2

Option B. x = 2 will be the answer.

1/5^2 = 7.56/45