Amanager wishes to build a 3-sigma range chart for a process. the sample size is five, the mean of sample means is 16.01, and the average range is 5.3. from table s6.1, the appropriate value of d3 is 0, and d4 is 2.115. what are the ucl and lcl, respectively, for this range chart? a. 6.3 and 0 b. 33.9 and 0 c. 11.2 and 0 d. 33.9 and 11.2 e. 31.91 and 0.11

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.

it should be a.

hope it