Match the following angles with their corresponding measurements.

1) m <1 = 63.5°
2) m <2 = 124°
3) m <3 = 29.5°
4) m <4 = 90°
5) m <5 = 54°
6) m <6 = 116.5°
7) m <7 = 121°

since 7 = 121 then EPD = 180-121 = 59, therefore arc ED = 59, making 3 = 1/2 59 = 29.5
8 = 1/2 arc BAED = 1/2 (121+59) = 1/2 (180) = 90
ADB = 1/2 BA = 1/2 68 = 34
PDH = 90, because where a radius meets a tangent is a rt. angle, so <4 = 90
PDH + ADB = <2 = 90+34 = 124
arc CD = 360 - (BAE+ED+CB) = 360-(180+72)
= 108
CBD = 1/2 arc CD = 1/2 108 = 54
that means BDC = 180-54-<8 = 126-90 = 36
so <5 = 90-36 = 54
BFD = 180-(<3+ADB) = 180-(29.5+34)
= 180-63.5 = 116.5
therefore <6 = 116.5 by rule vertical angles are = and <1 = 180-116.5 by rule supplementary angles = 180
<1 = 63.5

Yes, two vertical lines can be complementary