The area of a rectangle is 63ft ^2 and the length of the rectangle is 5ft more than double the width. find the dimensions of the rectangle.

Define Length and Width

Let the width be x
Width = x
Length = 2x + 5


Form equation and solve for x

x(2x + 5) = 63
2x² + 5x = 63
2x² + 5x - 63 = 0
(x+7)(2x-9) = 0
x = -7 (rejected, length cannot be negative) or 2x - 9 = 0
2x - 9 = 0
2x = 9
x = 9 ÷ 2 
x = 4.5 ft


Find Length and Width

Width = x = 4.5 ft
Length = 2x + 5 = 2(4.5) + 5 = 14 ft


Width = 4.5 ft , Length = 14 ft

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!