What is the slant height x of this square pyramid? express your answer in radical form.

the base of a regular pyramid is a hexagon. what is the area of the base of the pyramid?

1) What is the slant height x of this square pyramid? Express your answer in radical form

sin 60=x/4> x=4*sin 60> 4*(√3/2)> 2 √3 m

the answer Part 1) is 2 √3 m

2) The base of a regular pyramid is a hexagon. What is the area of the base of the pyramid?
[area of the base}=[area of hexagon]
[area of hexagon]=6*[area of triangle]

area of triangle
sin 60=a/14> a=(√3/2)*14> a=7√3 cm
cos 60=(b/2)/14> (b/2)=cos 60*14> (1/2)*14> (b/2)=7
base of triangle=2*7> b=14 cm

[area of triangle]=14*7√3 /2> 49√3 cm²
so
[area of hexagon]=6*[49√3]> 294√3 cm²

the answer part B) is 294√3 cm²

than do 23.50 times 18 and then divide your answer by 100 than you will get x.