The product of two consecutive integers is 30 . find the two integers. answer in the form of paired points with the lowest of the two integers first.

Let the first integer be x, the second one will be x+1.
the product of the integers will be:
x(x+1)=30
x^2+x=30
this can be written in the form of ax^2+bx+c=0, hence we shall have:
x^2+x-30=0
solving the quadratic we get:
x^2-5x+6x-30
x(x-5)+6(x-5
=(x-5)(x+6)
the numbers are x=5 and x=-6
Answer (-6,5) or (5,6)

It creates dogx^2 and then flip your answer and multiply by 2