The length of a rectangular room is one less than twice the width. the area of the room is 28 square feet. find the dimensions of the room.

The first step to solve this problem is to represent variables for the width and the length:

Let w = width of the rectangle

      2w – 1 = length of the rectangle

The formula to compute for the area of the rectangle is:

A = LW

Substituting the values and variables to the formula:

28 = w (2w – 1)

2w^2 – w = 28

2w^2 – w – 28 = 0

Solve the quadratic equation:

(2w + 7)(w – 4) = 0

w = -7/2 or w = 4

You cannot use the -7/2 because there is no negative measurement.

W = 4 feet

L = 2(4) – 1 = 7 feet

Therefore the dimension of the rectangle is 4 feet by 7 feet.

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: