Acylindrical piece of iron pipe is shown below. the wall of the pipe is 1.25 inches thick, the width is 8 inches and the length is 14 inches, what is the approximate inside volume of the pipe?

The following steps should be taken to answer the problem.

1. Deduct from the diameter (d) the thickness of the wall's pipe of 1.25in. 

d = 8in - (2(1.25in))
   = 5.5in

2. Get the radius (r), which is half of the diameter.

r = 5.5in/2
  = 2.75in

3. Get the volume of the cylinder with the formula, V = πr²h

V = 3.14 × (2.75)² × 14in
   = 332.45in³

Thus, the iron pipe can hold approximately 332.45 cubic inches.

There would be 36.35 pounds