Seven jars hold a total of 250 candies. they are lined up left to right from fullest to emptiest. the left-most jar has 72 candies, and the right-most jar has 13. no two jars hold the same number of candies. what is the positive difference between the greatest number of candies that could be in the second jar from the left, and the least number of candies that could be in that jar?

36  

Step-by-step explanation:

Here, the total number of candies in the jars = 250

The fullest jar or left most jar has candies = 72  

The right most or least candies containing jar has candies = 13

Thus, the sum of candies of middle 5 jars = 250-(72+13) = 165

The average of the these 5 jar = 165/5 = 33

Thus, the maximum number of candies in the middle jar = 33

⇒ The minimum number of candies in the second jar = 33 + 2 = 35 ( because no jar has equal number of candies and they are put in the decreasing order of candies)

But, the maximum number of candies in the second jar = 72 - 1 = 71

⇒ The difference between the maximum number of candies in second jar = 71 - 35 = 36

0.0076, if you meant 4.125 divided by 0.03125 it would be 132

step-by-step explanation:

first you have to move the decimal in 0.03125 over until its behind the 5 which is 5 places over. now the number is 3125

then you have to move the decimal in 4.125, 5 places over. now the number is 4,112,500.

now you divide like you would normally would and get 0.0076