Aplane left on time at noon on monday. it arrived at its destination at 8: 16 pm the same day, which was 16 minutes late. on average, how many seconds did the plane fall behind every fifteen minutes?

The plane fall behind 30 seconds every fifteen minutes

Step-by-step explanation:

If the plane was 16 minutes late,  so the correct time of arrival was 8 PM

First we have to calculate how many periods of 15 minutes we have in the whole flight.

x= t₂-t₁

t₁=noon=12 hs

t₂=8PM= 20hr

So,

x= 20- 12=8 hours

We have 4 periods of 15 minutes every hour,  so the total number of periods is the 8 hours of flight multiplied by 4

T=8*4= 32

Then we have to know how many seconds the fligth was late.  That will be

16 minutes  multiplied by 60 seconds by minute.

z= 16 *60= 960

We reach the final answer  dividing all the seconds that the flight was late (z) by the number of periods (T)

y= z/T=960/32

y= 30 seconds

d

gimmee one of those gold crowns!

~coco

step-by-step explanation:

at each of the parallel lines adjacent angles are supplementary. the angles have special names identifying their positions with respect to the parallel lines and transversal. they are corresponding angles, alternate interior angles, or alternate exterior angles. an angles is congruent to its matched angle.