The amount of money in an account may increase due to rising stock prices and decrease due to falling stock prices. mason is studying the change in the amount of money in two accounts, a and b, over time. the amount f(x), in dollars, in account a after x years is represented by the function below: f(x) = 10,125(1.83)x part a: is the amount of money in account a increasing or decreasing and by what percentage per year? justify your answer. (5 points) part b: the table below shows the amount g(r), in dollars, of money in account b after r years. r (number of years) 1 2 3 4 g(r) (amount in dollars) 9,638 18,794.10 36,648.50 71,464.58 which account recorded a greater percentage change in amount of money over the previous year? justify your answer.

Part A: The amount of money is increasing by 83% per year.

Part B: 95%

The function g(r) recorded the greatest percent change

Step-by-step explanation:

Assuming

Part A;

For the function   the percentage change is found by taking the slope between two consecutive points of the function and then seeing how it compares to the original amount

which is the amount increase per year. The percent this is of the original amount is

thus, the amount of money is increasing by 83% per year.

Part B:

The table gives shows us that the function is not linear, because there is no constant slope between the consecutive points, for example

and so on.

Now, let us find the percentage increase between the amount of money in consecutive years:  

we clearly see here that percent increase is 95%.

Since the function g(r) has greater percent increase than f(x), we conclude that g(r) recorded the greatest percent change over the previous year.

i dont know sorry

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!