The sum of two integers is 69. the greater integer is three more than two times the other. what is the greater integer?

the sum of three consecutive odd integers is 69. Find the integers.

1st: 2x-1
2nd: 2x+1
3rd: 2x+3

Equation:2x-1 + 2x+1 + 2x+3 = 69
6x + 3 = 69
2x + 1 = 23

So 2x-1 = 21
And 2x+3 = 25

let:
x be the first odd integer
x + 2 be the 2nd odd integer
x + 4 be the 3rd odd integer
solution:
1st odd integer + 2nd odd integer + 3rd odd integer = 69
x + (x+2) + (x+4)= 69

3x + 6 = 69
3x = 69 - 6
3x = 63 (dividing both sides by three)
x = 21

x=21
x+2=23
x+4=25 
therefore, the 1st integer is 21, the 2nd is 23 and the 3rd is 25..

5/ 1/3=15 i think sorry if im wrong