Guillermo is a professional deep water free diver. his altitude (in meters relative to sea level), xxx seconds after diving, is modeled by g(x)=\dfrac{1}{20}x(x-100)g(x)= 20 1 x(x−100)g, left parenthesis, x, right parenthesis, equals, start fraction, 1, divided by, 20, end fraction, x, left parenthesis, x, minus, 100, right parenthesis what is the lowest altitude guillermo will reach?

-125 meters.

Step by step explanation:  

We have been given that Guillermo is a professional deep water free diver. his altitude (in meters relative to sea level), x seconds after diving, is modeled by .

We have been given a quadratic function and the minimum value will occur at vertex.

First of all we will write it in standard quadratic form by using distribution property.

Now we will find vertex of our parabola using

Now let us substitute x=50 in our quadratic function to find lowest altitude of Guilermo.  

Therefore, the lowest altitude Guilermo will reach is -125 meters.          

answer:   14

step-by-step explanation:          

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answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.