How many solutions does the equation sin(4x)=1/2 have on the interval (0,2pi)?

2 solutions

Step-by-step explanation:

Given the equation sin(4x)=1/2, to know the total number of solutions that the equation has within the interval (0,2π), we will need to solve for x first.

sin(4x)=1/2

4x = arcsin1/2

4x = 30°

x = 30/4

x1 = 7.5° (This angle lies in the first quadrant)

Since sine is positive in the second quadrant as well and the angle in the second quadrant is (180°-theta) where theta is 7.5°, therefore;

x2 = 180-7.5°

x2 = 172.5°

Therefore 7.5° and 172.5° are the two solutions of x that falls within the range (0,2π)

false

step-by-step explanation:

i looked it up

ok

step-by-step explanation: