Aperpendicular bisector cd is drawn through point c on ab. if the coordinates of point a are (-3,2) and the coordinates of point b are (7, 6), the x-intercept of segment cd are what and what point lies on cd?

The following steps are needed: 1. find the function of ab with a(-3,2) and b(7,6)y(ab) = mx + b. calculate m = (y₂-y₁)/(x₂-x₁) = (6-2)/(7+3) = 4/10 → 2/5y(ab) = (2/5).x + b. calculate b; 6 = (2/) + b and b = 16/5y(ab) = (2/5).x +16/52. calculate the function y(cd) = mx + bwe know already m = -5/2, since cd is perpendicular to ab and hence the product of their slopes = -1y(cd) = -(5/2).x + bwe also know that y(cd) passes in the middle of ab, then let's calculate the coordinate of c, the midpoint of ab: x=(x₁+x₂)/2 and y=(y₁+y₂)/2)x= (-3+7)/2 and y=(2+6)/2x= 2 and y=4y(cd) = (-5/2).x +b4 = (-5/)+b and b = 9y(cd) =(-5/2)x + 9x intercept when y = 0 → 0= (-5/2)x +9 → x= 18/5so x intercept (18/5,0)  so the answer is  at point b.

Ionly know half the answer which is (18/5, 0)