The height h, in feet, of a projectile t seconds after launch is modeled by the equation h = 32t – 16t2. how long after launch does the projectile return to the ground? 2 seconds4 seconds14 seconds16 seconds

The correct option is A. 2 seconds

Step-by-step explanation:

The height h, in feet, of a projectile t seconds after launch is modeled by the equation h = 32·t – 16·t²

Now, we need too find the time after which the fired projectile touches the ground.

So, The fired projectile when touches the ground, The height of the projectile will become 0

⇒ Find the required time t when h = 0

⇒ 0 = 32·t - 16·t²

⇒ 0 = t × (32 - 16·t)

⇒ t = 0 or 32 - 16t = 0

⇒ 16t = 32

⇒ t = 2

So, t = 0 or t = 2

t cannot be 0 because initially the projectile is in the air as it has been already fired

⇒ t = 2 seconds

Therefore, The correct option is A. 2 seconds

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation:

da freeck kinda math is this just drop out

step-by-step explanation: