Mathematics, 29.07.2019 10:00 genyjoannerubiera

Asap 1. the area of a rectangular carpet is given by the trinomial 5x^2 - 3x - 14. what are the possible dimensions of the carpet? use factoring. a. (5x + 7) and (-x - 2) b. (5x + 7) and (x - 2) c. (5x - 7) and (x - 2) d. (5x - 7) and (x + 2) 2. the area of a rectangular barnyard is given by the trinomial 6x^2 + 7x – 20. what are the possible dimensions of the barnyard? use factoring a. 2x - 5 and 3x + 4 b. -2x - 5 and -3x + 4 c. 2x + 5 and 3x - 4 d. 2x - 5 and 3x - 4

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These are 2 questions and 2 answers:

1. Question 1: The area of a rectangular carpet is given by the trinomial 5x^2 - 3x - 14. What are the possible dimensions of the carpet? Use factoring.

5x^2 -3x -14

Explanation:

You might probe the different pairs of factors given in the answer choices to check wich product is equal to the oirginal polynomial or you can factor from zero.

I will show you how to factor that polynomial from zero:

1) given: 5x^2 - 3x - 14

2) multiply and divide by the leading coefficient =>

5 [5x^2 - 3x -14 ]

         5

3) Enter the the factor 5 inside the parenthesis:

5.5x^2 - 5.3x - 5.14

              5

4) rearrange conviniently to show (5x) as a common factir of the first two terms

(5x)^2 - 3(5x) - 70

              5

5) factor the numerator using 5x as common term of the two binomials:

(5x ) ( 5x   ) <> open the parenthesis
(5x - ) (5x + ) <> include the signs
(5x - 10) (5x + 7) <---> two numbers that add up - 3 and their product is - 70

=>

(5x - 10)(5x + 7)

         5

6) divide (5x - 10) by 5 => x - 2

7) factored expression

(x - 2) (5x + 7)

8) Conclusion: the answer is the option B. (5x + 7) and (x - 2)

2. Question 2. The area of a rectangular barnyard is given by the trinomial 6x^2 + 7x – 20. What are the possible dimensions of the barnyard? Use factoring

option C. (2x + 5)(3x - 4)

Explanation:

The procedure is the same of the question 1.

1) given: 6x^2 + 7x - 20

2) multiply numerator and denominator by 6 and rearrange to show (6x) as common factor ot the first two terms =>

(6x)^2 + 7(6x) - 120

              6
3) factor the numerador using 6x as common factor ot two binomials, and simplify:

(6x + )(6x - )
(6x + )(6x - )
(6x + 15) (6x - 8)

=>

(6x + 15)(6x -8)

           6

(6x + 15)(6x - 8)
=
        3.2

(6x + 15)      (6x - 8)
. =
      3                2

(2x + 5)(3x - 4)

4) option C. (2x + 5)(3x - 4)

Answer from: Quest

step-by-step explanation:

Which of the following are necessary when proving that the diagonals of a rectangle are congruent?

Answer from: Quest

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

Point z is equidistant from the sides of δrst. which must be true? ctzaszaszzsb

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Asap 1. the area of a rectangular carpet is given by the trinomial 5x^2 - 3x - 14. what are the poss...