Ari stocks shelves at the grocery store. he puts 35 cans of juice in each display case. the case has 4 shelves with an eqaul number of cans, and one shelf with only 3 cans. how many cans are on each of the equ shelves?

In this problem, we can conclude that in one display case there are 5 shelves in it. It was said that 4 shelves stores equal number of juice cans in it while the other one has only 3 cans. As a whole, Ari has 35 cans of juice. By placing 3 in one of the shelves, we can deduct it from 35 or (35 minus 3) so what we now have is 32 pieces of juice cans left to be equally distributed in the 4 shelves left. The equation will now be 32 divided 4 or 32/4 which will be equal to 8. So in each shelf from the 4 shelves will store 8 cans of juice equally. 

4+2=-2. 1+2=3. y=-2/3x+b. 2=4/3+b. 2/3=b. the answer is y= -2/3x+2/3

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm