Asap part a: explain why the x-coordinates of the points where the graphs of the equations y = 4x and y = 2x−1 intersect are the solutions of the equation 4x = 2x−1. (4 points) part b: make tables to find the solution to 4x = 2x−1. take the integer values of x between −4 and 4. (4 points) part c: how can you solve the equation 4x = 2x−1 graphically? (2 points)

A. The (x,y) coordinates where the equations y =4x and y = 2x - 1 intersect on a graph is the solution to that system of equations. When solving for this system of equations by substitution of y, the equation 4x = 2x -1 is obtained. So the x-coordinate obtained is both a solution to the equation 4x = 2x - 1 and the intersection point of the system of equations y = 4x and y = 2x - 1.

B. Idk about this part... Says to make a tables to solve for 4x = 2x - 1. 
If you make a table for Eq. #1. y = 4x and Eq. #2. y = 2x -1 maybe..

#1. y = 4x
x y
-4 .. -16
-3 .. -12
-2 .. -8
-1 .. -4 
 0 ... 0 
1 ... 4 
2 8
3 ... 12
4 ... 16

the solution to 4x = 2x - 1 ; the x-coordinate is not an integer value so Idk what the point of this is
4x = 2x - 1
4x - 2x = -1
2x = -1
x = -1/2
not an integer..

C. You can solve the equation 4x = 2x - 1 graphically by graphing y = 4x and y = 2x - 1 and identifying the x-coordinate at the point of intersection.

Idont knowgfdhdhfhggg.