The vertex form of a function is g(x) = (x – 3)2 + 9. how does the graph of g(x) compare to the graph of the function f(x) = x2? a. g(x) is shifted 3 units left and 9 units up. b. g(x) is shifted 3 units right and 9 units up. c. g(x) is shifted 9 units left and 3 units down. d. g(x) is shifted 9 units right and 3 units down.

For this case we have that the main function is given by:

First, we apply the horizontal transformation. To do this, we evaluate the function for x-3, that is, we move the graph 3 units to the right.

We apply the vertical transformation. To do this, add to the function 9 units, that is, we move the graph 9 units up.

We have then:

B.g (x) is shifted 3 units right and 9 units up.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

4th option is correct xy=-10

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