Which equation represents the general form a circle with a center at (–2, –3) and a diameter of 8 units? x2 + y2 + 4x + 6y – 51 = 0 x² + y² – 4x – 6y – 51 = 0 x2 + y2 + 4x + 6y – 3 = 0 x2 + y2 – 4x – 6y – 3 = 0

We know that
equation for a circle of radius r with center at (h,k) is given by
(x - h)² + (y-k)² = r²
center (h,k) is > (–2, –3)
(x-(-2))² + (y-(-3))² = 4²x² + 4x + 4 + y² + 6y + 9 = 16x² + 4x + y² + 6y - 3 = 0

the answer is
x² + y² + 4x + 6y - 3 = 0