Solve the system algebraically. check your work. 4x + 2y = 10 3x + 2y = 6 {( a0)}

x = 4 and y = -3.

Step-by-step explanation:

Given  : 4x + 2y = 10  and 3x + 2y = 6.

To find : Solve the system algebraically. Check your work.

Solution : We have given that

4x + 2y = 10 (1)

3x + 2y = 6.(2)

Subtracting equation 2 from 1

4x + 2y = 10

(-)3x + (-)2y =(-) 6.

x + 0 =  4

x =4

Plug x = 4 in equation 1

4 (4) + 2y = 10.

16 + 2y = 10.

2y  = 10 -16.

2y  = -6.

On dividing by 2 both sides

y = -3.

Check:

Plug the values x =4 , y =-3 in equation 1

4 (4) + 2 ( -3) = 10

16 -6 = 10

10 =10

Verify,

Therefore, x = 4 and y = -3.

answer: just subtact the units and then add the non negative : happy to

step-by-step explanation:

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step-by-step explanation: