Find three consecutive integers that have an average of 53

Consecutive intergers are 1 away from each other so
numbers are
x,x+1,x+2

average is found by adding the numbers up and dividng the total by the number of numbers you have
so we add x+x+1+x+2 up and divide it by 3 (3 numbers)
x+x+1+x+2=x+x+x+1+2=3x+3
(3x+3)/3=53
[3(1x+1)]/3=53
3/3 times 1x+1=52
1x+1=53
subtract 1 from both sides
x=52

subsitute
x+1 is the second
x+2 is the third
x+1=52+1=53
x+2=52+2=54

numbers are 52,53,54