Four times the larger of two numbers is equal to seven times the smaller. the sum of the numbers is 22. what are the numbers?

The larger is 14 the smaller is 8

Let the larger number be L and the smaller be S
So we know that

1) L+S=22
And
2)4L=7S
From equation 1) we get L=22-S

Substitute this into equation 2) to get 4(22-S)=7S
88-4S=7S
88=11S
S=8. The smaller number is 8

As they total 22 the larger number is 14.
Check: 4x14=7x8. Yes

Solution 2:

Let x= larger number
And let y= smaller. umber

Now we are told that:
4x=7yeq1
We are also told that:
x + y=22eq2

Substitution method looks easier.

From eq1 x=(7/4)y. Substitute this into eq2
(7 /4)y +y=22
(7/4)y+(4/4)y=22
(11/4)y=22 multiply each side by 4
11y=88
y=8

From eq2, x+8=22
x=14

Hope this helps

cosine

step-by-step explanation:

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk