Solve the equation using the quadratic formula. x squared minus 4 x plus 3 equals 0 (1 point)x equals 2 semicolon x equals 4x equals 0 semicolon x equals 4x equals 1 semicolon x equals 3x equals negative 1 semicolon x equals 92. solve the equation using the quadratic formula. x squared plus 10 x equals negative 25 (1 point)x equals 5x equals negative 5x equals 15x equals 253. using the discriminant, determine the number of real solutions. negative 4 x squared plus 20 x minus 25 equals 0 (1 point)no real solutionsone real solutiontwo real solutions4. using the discriminant, determine the number of real solutions.2 x squared plus 7 x minus 15 equals 0 (1 point)no real solutionsone real solutiontwo real solutions5. using the discriminant, determine the number of real solutions. negative 2 x squared plus x minus 28 equals 0 (1 point)no real solutionsone real solutiontwo real solutions6. if the discriminant of a quadratic is zero, determine the number of real solutions. (1 point)no real solutionsone real solutiontwo real solutions7. solve the equation using the quadratic formula.3 x squared equals 2 left-parenthesis 2 x plus 1 right-parenthesis (1 point)x equals startfraction 3 plus minus startroot of 13 endroot over 6 endfractionx equals startfraction 2 plus minus startroot of 10 endroot over 3 endfraction x equals one-sixth semicolon x equals one-halfx equals 3 semicolon x equals negative 18. solve the equation using any technique. x squared plus 8 x plus 12 equals 0 (1 point)x equals negative 4 semicolon x equals 4x equals negative 6 semicolon x equals negative 2x equals 3 semicolon x equals 7x equals 6 semicolon x equals 89. solve the equation using any technique.6 x squared minus 5 x minus 1 equals 0 (1 point)x equals one-fifth semicolon x equals one thirdx equals 2 semicolon x equals 6x equals 3 semicolon x equals negative one-halfx equals negative one-sixth semicolon x equals 110. solve the equation using any technique. x squared equals 3 x minus 1 (1 point)x equals startfraction 2 plus minus startroot 7 endroot over 3 endfractionx equals startfraction 1 plus minus startroot 3 endroot over 2 endfractionx equals startfraction 3 plus minus startroot 5 endroot over 2 endfractionx equals startfraction negative 2 plus minus 2 startroot 3 endroot over 3 endfraction