Simplify expression- 11. (n^4)^8 13. (q^10)^10 15. (x^3)^-5 17. (z^8)^0z^5 19. (c^3)^5(d^3)^0 @phebe last one i promise lol

In all these expressions you have a power of a power. 
You can solve them simply multiplying the exponents.
Remember that any quantity raised to the zero is equal to 1.
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11) (n^4)^8 = n^(4×8) = n^32

13) (q^10)^10 = q^(10×10) = q^100

15) (x^3)^-5 = x^[3×(-5)] = x^(-15)

17) (z^8)^0z^5 = z^(8×0) z^5 = z^0 z^5 = 1×z^5 = z^5

19) (c^3)^5(d^3)^0 = c^(3×5) d^(3×0) = c^15 d^0 = c^15×1 = c^15

I’m going to infer you said parallel.solve for yy= -1/2x+7/4lines that are parallel have the same slope, different y intercept.so we know m is -1/2then from there solve for y intercept.