Asix sides dice rolls twice. what is the probability that the first roll is a even number and the second roll is a number greater than 4?

Answer - 1/6

EXPLANATION

For a six sides dice:
Possible numbers are: 1, 2, 3, 4, 5, and 6
Total of 6 possible numbers

Possible even number outcomes are: 2, 4, and 6
Total of 3 outcomes out of 6 possibilities
Probability that the roll is a even number, p(A) = 3/6
p(A) = 3/6 = 1/2

Possible outcomes greater than 4 are: 5 and 6
Total of 2 outcomes out of 6 possibilities
Probability that the roll is a number greater than 4, p(B) = 2/6
p(B) = 2/6 = 1/3

The probability that the first roll is a even number and the second roll is a number greater than 4 = p(A and B)
p(A and B) = p(A) x p(B)

p(A) = 1/2
p(B) = 1/3
p(A and B) = p(A) x p(B)
= 1/2 * 1/3
= 1/6

This is too long-standing now get out