The standard addition algorithm below is being used to add three two-digit numbers 4z + 27 + x 5 equals y 14. if x, y, and z each represent a different digit from 0 to 9 what is the value of (x)(y)(z)?

For the units positions of all numbers we have:

From this we can conclude that total sum of these three numbers is 14. Number 1 we carry to next step. So we have:


For the tens positions of all numbers we have:

The extra number 1 on left side comes from the carry from last step. Similar to ones position we know that total sum is 11.


Now we insert x and z to find out y:


Now we need to find out the product of these three numbers: