The cost c (in dollars) for the care and maintenance of a horse and carriage is c=15x+2000, where x is the number of rids. $35 per ride. write an equation for the revenue r in terms of the numbers of rides. how many rides are needed to break even?

The equation would be R(x)=35x and it would take 100 rides.

To find the point where the company breaks even we set the cost equation C(x) equal to the revenue function R(x):

15x+2000=35x

We can't have a variable on both sides, so we subtract 15x from both sides:
15x+2000-15x=35x-15x
2000=20x

Now we divide both sides by 20:

2000/20 = 20x/20
100 = x

The answer would be 315 because you need to subtract