The base of a ladder is 25 meters due west of a burning building. if the angle of elevation of the ladder is 51°, how long is the ladder (round to the nearest meter)? a)33 meters b) 34 meters c) 39 metersd) 40 meters

The ladder is approximately 40 meters long to the nearest tenth.

The information will form a right angle triangle.

The base of the ladder 25 meters due west of the burning building is the base(adjacent side) of the triangle formed.

How long is the ladder describe the hypotenuse of the triangle formed.

Therefore, using trigonometric ratio we can find the length of the ladder as follows:

cos 51 = adjacent / hypotenuse

cos 51 = 25 / hypotenuse

hypotenuse = 25 / cos 51°

hypotenuse = 25 / 0.62932039105

hypotenuse = 39.7253932266 meters

hypotenuse ≈ 40 meters

Therefore, the ladder is  approximately 40 meters long to the nearest tenth

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3. parallelogram

step-by-step explanation:

we turn each of our sides into direction vectors

ab=b-a=(3 - 7, 1 - 0) = (-4, 1)

bc=c-b=(1,6)

cd=d-c=(4,-1)

da=a-d=(-1,-6)

we see how the opposite sides have negated direction vectors; this is characteristic of a parallelogram.   we have congruent sides ab=cd and bc=da with unequal lengths because 1^2+6^2 is different from (-4)^2+1^2.   so it's not a square or a rhombus.  

we check the dot product of direction vectors of adjacent sides.   we have

ab dot bc = -4(1) + 1(6) = 2

that's not zero so the sides are not perpendicular.   we've ruled out rectangle.

the direction vectors indicate two pairs of congruent parallel sides, so we choose parallelogram over trapezoid.

huh? im pretty sure it is in 199

step-by-step explanation: