Beth says that the graph of g(x) = + 1 is a translation of 5 units to the left and 1 unit up of f(x) = . she continues to explain that the point (0, 0) on the square root function would be translated to the point (–5, 1) on the graph of g(x). is beth’s description of the transformation correct? explain.

Idon't have the functions but you refer to (0,0) on the square root function so i am guessing that .beth explains that g(x) is a translation of f(x) 5 units to the left and 1 unit up.let's start with the 1 unit up. to shift a function f(x) up or down we add a constant (a positive constant a moves it up a units and a negative constant b moves it down b units). to move f(x) up 1 unit we write f(x) + 1. to move a function left or right we add a constant to the independent variable (usually we use x). adding a positive constant c moved the graph left c units and adding a negative constant d moves it right d units. so to move f(x) left 5 units we would write f (x+5).putting those two together, if our function is f(x) then the translated function (left five and up one) is f(x+5)+1.if then the function and beth would be right that the point (0,0) would be translated to (-5,1).