what is the solution to the following system? 5x+2y+z=4 x+2z=4 2x+y-z=-1a. x = 0, y = 1, z = 2b. x = 1, y = –1, z = 2c. x = 1, y = 0, z = –1d. x = 2, y = 1, z = 0

We solve the system by applying the following steps:
 1) Write two of the variables in terms of the third variable. For this case we write x, y in terms of z.
 2) Substitute the expressions in the first equation since it relates all the variables.
 3) Clear z.
 4) with the value of z, find x, y
 
 A. x = 0, y = 1, z = 2
 See attached image.