Yolanda is planning to put a pool in her backyard. the model below gives the reduced measures for diameter and depth the yard space is large enough to have a pool that has a diameter of 27 feet. if yolanda wants to keep the pool in proportion to the model, what will be the depth of the pool? 4.5ft 5 ft 6 ft 6.75 ft

the image of the problem was not found. as a way to  understand the problem, an example image is attached.

  let

>   depth  of the real pool

>   diameter of the real pool 

> depth  of the model pool

> diameter of the model pool 

> proportion

  we know that

p= (hr/dr)=(hm/dm)

  therefore

(hr/dr)=(hm/dm)

  i  use cross products to find a hr

hr*dm=hm*> hr=[hm*dr]/dm     

  we know

hm=2 ft

dm=8 ft

dr=27 ft

  hr=[2*27]/ > hr=6.75 ft     

the answer is

hr=6.75 ft 

the expression (1.26)2t reveals the approximate rate of increases in the number of plants semiannually.

hope this : )

answer: median

step-by-step explanation:

the median is the middle value when a data set is ordered from least to greatest