Find the probability when a couple has 6 children at at least one of them is a boy

Try this solution:
1. Probability (P): 1-[probability_all_the_girls]
2. P=1- 1/2⁶=1- 1/64=63/64≈0.984375.

Note: P_all_the_g=[needed_cases]/[all_possible_cases], where needed cases=1 (all the girls means ''), and all possible cases=2⁶=64 (all possible cases means '';'';g';'gg';'gggbbb';'bb';b';'b', etc. Total 64 combinations.)

Bruh sound effect #2