Equation a: 3x + y = 6 equation b: 6x - 2y = 4 equation c: y = 3x - 2 equation d: y = 1 3 x + 7 which two lines are perpendicular?

Given:
A: 3x + y = 6 
B: 6x - 2y = 4 
C: y = 3x - 2
D: y = 1/3 x + 7

To figure out which two lines are perpendicular, we must look at the slopes of each one after putting them into standard form, y = mx + b.

Standard Form:
A: y = -3x + 6
B: y = 3x - 2
C: y = 3x - 2
D: y = (1/3)x + 7

Lines are perpendicular when their slopes are opposite inverses of eachother.

The opposite of -3 is 3 and the inverse of 3 is 1/3.

Therefore, lines A and D are perpendicular to one another :)