Write a pair of numbers such that the value of the 7 in the first number is 1000 times the value of the 7 in the second number, and the value of the 3 in the first number is 100 times the value of the 3 in the second number

The pair of numbers can be 70300 and 73.

Let us assume that the second number is 73. 

7 in 73 is 70 or 7 x 10
3 in 73 is 3 or 3 x 1

Since the 2nd 7 is 70 and the 1st 7 should be 1000 times the value of the 2nd number. then 70 x 1000 = 70000

The 1st 3 is said to be 100 time the value of 3 in the second number. 

3 x 100 = 300

first number: 70000 + 300 = 70300
second number: 70 +     3 =       73    

Ibelieve the answer is c i worked it out three times but if my answer is wrong someone correct me

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