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Mathematics, 31.07.2019 11:30 crystalhoff6176
How do i find the value of x that is placed as the numerator? ×/5+1=-6
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Mathematics, 20.06.2019 18:04
Here is their argument. given the obtuse angle x, we make a quadrilateral abcd with ∠dab = x, and ∠abc = 90◦, and ad = bc. say the perpendicular bisector to dc meets the perpendicular bisector to ab at p. then pa = pb and pc = pd. so the triangles pad and pbc have equal sides and are congruent. thus ∠pad = ∠pbc. but pab is isosceles, hence ∠pab = ∠pba. subtracting, gives x = ∠pad−∠pab = ∠pbc −∠pba = 90◦. this is a preposterous conclusion – just where is the mistake in the "proof" and why does the argument break down there?
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Mathematics, 21.06.2019 19:30
Can someone me with the property questions for 12 13 and 14 plz
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How do i find the value of x that is placed as the numerator? ×/5+1=-6...
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