In a quadrilateral abcd, ab ∥ dc and ad ∥ bc . find the perimeter of δcod if point o is the intersection of the diagonals and ac = 20 in, bd = 20 in, ab = 13 in.

33

Step-by-step explanation:

As the opposite sides of a quadrilateral are parallel and equal in length so

(AB) = (CD) =13

And the diagonals of a quadrilateral bisect each other at their intersection point (O in this case), so length of side OC will be the half of diagonal AC.

(OC) =  (AC) /2

(OC)=20/2

(OC) =10

Similarly,  

(OD) =10

Now,

Perimeter of Triangle OCD = (OC) + (CD)  + (OD)

=10+13+ 10

=33

one of each metals

step-by-step explanation: