(1.3t3 + 0.4t2 – 24t) – (0.6t2 + 8 – 18t) what is the additive inverse of the polynomial being subtracted?

To solve this problem you must apply the proccedure shown below:
 1. You have that the the polynomial being subtracted is 0.6t²+8-18t, therefore,  to find the additive inverse of the polynomial, you must multiply it by -1, as following:
 (0.6t²+8-18t)
 (-1)(0.6t²+8-18t)
 2. Therefore, you obtain the following result:
 -0.6t²-8+18t
 Then, tas you can see, the  answer is -0.6t²-8+18t.