If you flip two coins 12 times, what is the best prediction possible for the number of times both coins will land on tails? times

3

Step-by-step explanation:

I know I'm late by 4 years but the answer is 3. This is because if you divide 12 by the 2 coins you'll get 6. You then need to divide it in half again because it's asking for both coins not only one. This gets you the answer of 3. I'm only writing this because other people may need help, 4 years later-

i'm pretty sure it's 477,585,296, but perhaps my math is incorrect.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.