When rolling a number cube with sides labeled 1 through 6, what is the probability of rolling a number greater than 2?

express your answer in simplest form

4/ 6 or in simplest, 2/3. I know this bc there's only 4 numbers greater than 2. there for me the fraction would be 4/6 the six for the sides and the four for the number of aides greater than two. :)))

So since it says greater than 2 is would not include 2 it would be 3,4,5,6. so your answer would be 4/6 but you need it in simplest for so it would be 2/3!
HOPE THIS HELPED ;D

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12