Given that f(x) = x2 − 3x + 3 and g(x) = the quantity of x minus one, over four , solve for f(g(x)) when x = 5. (1 point)

First we write both functions:
 f (x) = x ^ 2 - 3x + 3
 g (x) = ((x-1) / (4))
 We now make the composition of functions:
 f (g (x)) = ((x-1) / (4)) ^ 2 - 3 (((x-1) / (4))) + 3
 We now evaluate for x = 5:
 f (g (5)) = ((5-1) / (4)) ^ 2 - 3 (((5-1) / (4))) + 3
 f (g (5)) = 1
 
 f (g (5)) = 1

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